From fbeb01ce301803ceb9dcc6a128f705bdcfad9052 Mon Sep 17 00:00:00 2001
From: "Andy K. Massimino" <massimino@gatech.edu>
Date: Wed, 22 Nov 2017 11:24:11 -0500
Subject: [PATCH] Add test cases for #10

---
 test/issues/10/legacy.vim | 32 ++++++++++++++++++++++++++++++++
 test/issues/10/string.vim |  8 ++++++++
 2 files changed, 40 insertions(+)
 create mode 100644 test/issues/10/legacy.vim
 create mode 100644 test/issues/10/string.vim

diff --git a/test/issues/10/legacy.vim b/test/issues/10/legacy.vim
new file mode 100644
index 0000000..6c371ba
--- /dev/null
+++ b/test/issues/10/legacy.vim
@@ -0,0 +1,32 @@
+
+if "(foo)"
+
+	let x = "(foo)"
+
+endif
+
+	( )
+
+let x = (   "( )"   )
+
+let y =  "("
+	\ . ")"
+
+	    "("
+		)
+	\ . ")"
+
+let z =  (   '( ' ) . ' )'
+
+let a = " if   endif "
+							*cpo-M*
+	M	When excluded, "%" matching will take backslashes into
+		account.  Thus in "( \( )" and "\( ( \)" the outer
+		parenthesis match.  When included "%" ignores
+		backslashes, which is Vi compatible.
+
+let b = '\(  \)'
+let c = "\\(  \\)"
+
+let d = "( \\(  )"  .  "\\(  " . '\(  \)' . "\\)"
+
diff --git a/test/issues/10/string.vim b/test/issues/10/string.vim
new file mode 100644
index 0000000..9d21130
--- /dev/null
+++ b/test/issues/10/string.vim
@@ -0,0 +1,8 @@
+
+function String()
+
+  let output = filter(list, "matchstr(v:val, '^\s*\zsfoo\ze\\(bar\\|baz\\)')")
+  let output = filter(list, 'matchstr(v:val, ''^\s*\zsfoo\ze\(bar\|baz\)'')')
+
+endfunction
+